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40 perches A M P L E ABCD acres altitude Answer base bearing blank line centre chains and links chord circle circumferentor Co-fine Co-ſecant Co-tang column contained cyphers decimal divided Dēg draw drawn east edge feet field-book figures four-pole chains half the sum inches instrument latitude logarithm measure meridian distance multiplied needle number of degrees off-sets P R O parallel parallelogram perches perpendicular piece of ground Plate pole prob produćt protractor quotient radius right angles right line scale of equal Secant second station sect semicircle side sights sine stationary distance sun's survey T H E taken tance tangent thence theo theodolite thro triangle ABC trigonometry true amplitude two-pole chains vane variation whence x A M P L E
Page 32 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 94 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Page 23 - Four quantities are said to be in proportion when the product of the extremes is equal to that of the means : thus if A multiplied by D, be equal to B multiplied by C, then A is said to be to B as C is to D.
Page 95 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Page 37 - ABDE+ACGF the sum of the squares —BKLH-\-KCML, the sum of the two parallelograms or square BCMH; therefore the sum of the squares on AB and AC is equal to the square on BC.
Page 24 - Things that are equal to one and the same thing, are equal to each other. 2. Every whole is greater than its part. % 3. Every whole is equal to all its parts taken together. 4 If to equal things, equal things be added, the whole will be equal. 5. If from equal things, equal things be deducted the remainders will be equal.
Page 36 - XIII. •All parallelograms on the same or equal bases and between the same parallels...
Page 182 - VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor.