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1)th term 12 rods 3d power 3d root 5th power a b c A's share added algebra algebraic quantities apples approximate root Arith arithmetic becomes binomial Binomial Theorem bought breadth bushels cents apiece coefficient compound interest compound quantities consisting contain decimal denominator difference divide the number dividend divisor equal equation example exponent expressed factor figure formula fourth fraction gallons geometrical progression gives greater Hence horse length less Let a denote Let the learner letter logarithm merator miles multiplicand number of dollars number of terms º º observe pears question quotient remainder required to find rods rule second power second root second term shillings sold subtracted Suppose third power third root twice unknown quantity whole number yards zero
Page 186 - The 3d power of (2 a — rf)4 is (2a — rf)^«+« = (2a — d)4x3=(2a — d)". That is, any quantity, which is already a power of a compound quantity, may be raised to any power by multiplying its exponent by the exponent of the power to which it is to be raised. 7. Express the 2d power of (3 b — c)4. 8. Express the 3d power of (a — c -J- 2 d)*. 9. Express the 7th power of (2 a* — 4 c3)3.
Page 101 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 92 - It will be seen by the above section that if both the numerator and denominator be multiplied by the same number, the value of the fraction will not be altered...
Page 2 - District Clerk's Office. BE IT REMEMBERED, That on the seventh day of May, AD 1828, in the fifty-second year of the Independence of the UNITED STATES OF AMERICA, SG Goodrich, of the said District, has deposited in this office the...
Page 21 - A cask, which held 146 gallons, was filled with a mixture of brandy, wine, and water. In it there were 15 gallons of wine more than there were of brandy, and as much water as both wine and brandy. What quantity was there of each...
Page 232 - I, n, d, and. S; any three of which being given, the other two may be found, by combining the two equations. I shall leave the learner to trace these ' himself as occasion may require. Examples in Progression by Difference.
Page 35 - How many days did he work, and how many days was he idle ? Let x = the number of days he worked.
Page 229 - Hence, any term may be found by adding the product of the common difference by the number of terms less one, to the first term.
Page 273 - A gentleman bought a rectangular lot of valuable land, giving 10 dollars for every foot in the perimeter. If the same quantity had been in a square, and he had bought it in the same way, it would have cost him $33 less ; and if he had bought a square piece of the same perimeter he would have had 12^ rods more.