Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain Practical System of Arithmetick, Adapted to the United States |
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Page 169
A TABLE OF RATIOS . Rate per cent . 1 Rutio . | Rute per cent . Ratio . 3 , 03 5 , 055 4 , 04 6 , 045 , 065 5 , 05 7 , 07 Ratio is the simple interest of il . for one year ; or in federal money , of $ 1 for one year , at the rate per ...
A TABLE OF RATIOS . Rate per cent . 1 Rutio . | Rute per cent . Ratio . 3 , 03 5 , 055 4 , 04 6 , 045 , 065 5 , 05 7 , 07 Ratio is the simple interest of il . for one year ; or in federal money , of $ 1 for one year , at the rate per ...
Page 170
211,45 Principal , 05 Ratio , 10,5725 Interest for one year . 5 Multiply by the time . 52,8625 Ans . = $ 52 , 86cts . 20 . 2. What is the interest of 6451. 10s . for 3 years , at i per cent . per annum ? £ 615,5x06x3 = 116,190 = 6116 38 ...
211,45 Principal , 05 Ratio , 10,5725 Interest for one year . 5 Multiply by the time . 52,8625 Ans . = $ 52 , 86cts . 20 . 2. What is the interest of 6451. 10s . for 3 years , at i per cent . per annum ? £ 615,5x06x3 = 116,190 = 6116 38 ...
Page 171
Subtract the principal from the amonnt ; diviele the remainder by the product of the ratio and principal ; and the quotient will be the time . EXAMPLES . 1. In what time will 950 dois . 75 cts . amount to 1235 dollars , 97,5 cents ...
Subtract the principal from the amonnt ; diviele the remainder by the product of the ratio and principal ; and the quotient will be the time . EXAMPLES . 1. In what time will 950 dois . 75 cts . amount to 1235 dollars , 97,5 cents ...
Page 173
... 104 41600 Balance , 400 June 1 , Rec'd in full of principal , 400 388600 Then 388600 , 06 Ratio . $ cts . m . 365 23316,00 ( 63,879 Ans . = 63 87 9+ The following Rule for computing interest on any note , or obligation , when there ...
... 104 41600 Balance , 400 June 1 , Rec'd in full of principal , 400 388600 Then 388600 , 06 Ratio . $ cts . m . 365 23316,00 ( 63,879 Ans . = 63 87 9+ The following Rule for computing interest on any note , or obligation , when there ...
Page 197
PROBLEM I. The first term , the last term ( or the extremes ) and the ratio given , to find the sum of the series . RULE . Multiply the last term by the ratio , and from the product subtract the first term ; then divide the remainder by ...
PROBLEM I. The first term , the last term ( or the extremes ) and the ratio given , to find the sum of the series . RULE . Multiply the last term by the ratio , and from the product subtract the first term ; then divide the remainder by ...
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