Practical Arithmetic, by Induction and Analysis |
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Page 5
... Cloth Measure , ...... Wine or Liquid Measure , ........ Ale or Beer Measure , .. Time Measure , ...... Circular Measure , .. Promiscuous Examples in Reduction , ......... Addition of Compound Numbers , ... Subtraction of Compound ...
... Cloth Measure , ...... Wine or Liquid Measure , ........ Ale or Beer Measure , .. Time Measure , ...... Circular Measure , .. Promiscuous Examples in Reduction , ......... Addition of Compound Numbers , ... Subtraction of Compound ...
Page 36
... cloth are there in 3 pieces , each containing 123 yards ? OPERATION . 123 multiplicand . 3 multiplier . SOLUTION . Having placed the multi- plier under the multiplicand , as in the margin , say , 3 times 3 units are 9 units , which ...
... cloth are there in 3 pieces , each containing 123 yards ? OPERATION . 123 multiplicand . 3 multiplier . SOLUTION . Having placed the multi- plier under the multiplicand , as in the margin , say , 3 times 3 units are 9 units , which ...
Page 48
... cloth can you purchase for $ 30 ? 9. How many lead pencils , at 5 cents apiece , can you buy for 35 cents ? 11. A man has 63 pounds of butter , and wishes to put it into boxes , each containing 7 pounds : how many boxes will be required ...
... cloth can you purchase for $ 30 ? 9. How many lead pencils , at 5 cents apiece , can you buy for 35 cents ? 11. A man has 63 pounds of butter , and wishes to put it into boxes , each containing 7 pounds : how many boxes will be required ...
Page 64
... cloth , of 73 yards each : and 12 pieces , of 88 yards each : how many yards in all ? Ans . 1713 yards . 8. I spend 99 cents a day : how many cents will I spend in 49 years , of 365 days each ? Ans . 1770615 . 9. An Encyclopedia ...
... cloth , of 73 yards each : and 12 pieces , of 88 yards each : how many yards in all ? Ans . 1713 yards . 8. I spend 99 cents a day : how many cents will I spend in 49 years , of 365 days each ? Ans . 1770615 . 9. An Encyclopedia ...
Page 76
... clothes for $ 56.93 7 ; hat for $ 8.50 ; and a whip for $ 2.31 3 : what was the amount ? Ans . $ 311.62 5 6. A person has due him , five hundred and four dollars , six cents , three mills ; $ 420 , 19 cents , 7 mills ; one hundred and ...
... clothes for $ 56.93 7 ; hat for $ 8.50 ; and a whip for $ 2.31 3 : what was the amount ? Ans . $ 311.62 5 6. A person has due him , five hundred and four dollars , six cents , three mills ; $ 420 , 19 cents , 7 mills ; one hundred and ...
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Common terms and phrases
acres amount annexed apples bank discount barrels bought bushels cancel ciphers cloth common fraction composite number Compound Numbers contained cost cube root cubic denominator denotes diameter difference dividend divisible dollars Dry Measure equal expressed feet figure find the interest gain gallons Give examples given number greatest common divisor Hence hundred hundredths improper fraction inches least common multiple lowest terms MEASURE meter mills mixed number multiplicand multiply NOTE number of terms OPERATION payment pecks pints pounds prime factors principal proper fraction proportion quarts quotient rate per cent ratio Ray's Test Examples Reduce remainder Rule selling side simple fraction Simple Numbers sold solid contents SOLUTION square root subtract tens tenths third thousand thousandths U. S. Money units weight whole number write yards
Popular passages
Page 158 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 179 - To multiply a decimal by 10, 100, 1000, &c., remove the decimal point as many places to the right as there are ciphers in the multiplier ; and if there be not places enough in the number, annex ciphers.
Page 63 - TABLE. 10 Mills (m.) = 1 Cent . . ct. 10 Cents = 1 Dime . . d. 10 Dimes = 1 Dollar . $. 10 Dollars = 1 Eagle . E.
Page 137 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 150 - We have seen that multiplying by a whole number is taking the multiplicand as many times as there are units in the multiplier.
Page 222 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced, add it to the principal, and deduct the payment from the sum total. If there be after payments made, compute the interest on the balance due to the next payment, and then deduct the payment as above; and, in like manner, from one payment to another, till all the payments are absorbed ; provided the time between one payment and another be one year or more.
Page 219 - The rule for casting interest, when partial payments have been made, is to apply the payment, in the first place, to the discharge of the interest then due. If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due.
Page 52 - III. — 1. Cut off the ciphers at the right of the divisor, and as many figures from the right of the dividend. 2. Divide the remaining figures in the dividend by the remaining figures in the divisor.
Page 282 - Hence, when the first term, the common difference, and the number of terms, are given, to find the last term...
Page 219 - If the payment be less than the interest, the surplus of interest must not be taken to augment the principal; but interest continues on the former principal until the period when the payments, taken together, exceed the interest due, and then the surplus is to be applied...