Practical Arithmetic, by Induction and Analysis |
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Page 21
... acres . 132 acres . 25 acres . 397 acres . Lastly , 1 hundred and 2 hundreds are 3 hun- dreds , which write in hundreds ' place , and the work is complete . Questions to be solved and explained as above . The sign $ stands for the word ...
... acres . 132 acres . 25 acres . 397 acres . Lastly , 1 hundred and 2 hundreds are 3 hun- dreds , which write in hundreds ' place , and the work is complete . Questions to be solved and explained as above . The sign $ stands for the word ...
Page 36
... that when the multiplicand is a concrete number , the product must be concrete . REM . 2. What does the multiplier show ? What must it be considered ? OPERATION . 6. At $ 43 an acre , what 36 RAY'S PRACTICAL ARITHMETIC .
... that when the multiplicand is a concrete number , the product must be concrete . REM . 2. What does the multiplier show ? What must it be considered ? OPERATION . 6. At $ 43 an acre , what 36 RAY'S PRACTICAL ARITHMETIC .
Page 37
Joseph Ray. OPERATION . 6. At $ 43 an acre , what will 5 acres of land cost ? SOLUTION . - Say , 5 times 3 ( units ) are 15 ( units ) ; write the 5 ( units ) in units ' place , and carry the 1 ( ten ) ; then , 5 times 4 ( tens ) are 20 ...
Joseph Ray. OPERATION . 6. At $ 43 an acre , what will 5 acres of land cost ? SOLUTION . - Say , 5 times 3 ( units ) are 15 ( units ) ; write the 5 ( units ) in units ' place , and carry the 1 ( ten ) ; then , 5 times 4 ( tens ) are 20 ...
Page 41
... acres of land cost , at $ 124 an acre ? Ans . $ 2976 . 3. How far will a ship sail in 56 weeks , at the rate of 2395 miles per week ? Ans . 134120 miles . 4. How many pounds of iron are there in 54 loads , each weighing 2873 pounds ...
... acres of land cost , at $ 124 an acre ? Ans . $ 2976 . 3. How far will a ship sail in 56 weeks , at the rate of 2395 miles per week ? Ans . 134120 miles . 4. How many pounds of iron are there in 54 loads , each weighing 2873 pounds ...
Page 57
... acre , how many acres of land can be bought for $ 3465 ? Ans . 231 acres . 25. If a man travel 26 miles a day , in how many days will he travel 364 miles ? Ans . 14 days . 26. If $ 1083 be divided equally among 19 men , how many dollars ...
... acre , how many acres of land can be bought for $ 3465 ? Ans . 231 acres . 25. If a man travel 26 miles a day , in how many days will he travel 364 miles ? Ans . 14 days . 26. If $ 1083 be divided equally among 19 men , how many dollars ...
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Common terms and phrases
acres amount annexed apples bank discount barrels bought bushels cancel ciphers cloth common fraction composite number Compound Numbers contained cost cube root cubic denominator denotes diameter difference dividend divisible dollars Dry Measure equal expressed feet figure find the interest gain gallons Give examples given number greatest common divisor Hence hundred hundredths improper fraction inches least common multiple lowest terms MEASURE meter mills mixed number multiplicand multiply NOTE number of terms OPERATION payment pecks pints pounds prime factors principal proper fraction proportion quarts quotient rate per cent ratio Ray's Test Examples Reduce remainder Rule selling side simple fraction Simple Numbers sold solid contents SOLUTION square root subtract tens tenths third thousand thousandths U. S. Money units weight whole number write yards
Popular passages
Page 158 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 179 - To multiply a decimal by 10, 100, 1000, &c., remove the decimal point as many places to the right as there are ciphers in the multiplier ; and if there be not places enough in the number, annex ciphers.
Page 63 - TABLE. 10 Mills (m.) = 1 Cent . . ct. 10 Cents = 1 Dime . . d. 10 Dimes = 1 Dollar . $. 10 Dollars = 1 Eagle . E.
Page 137 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 150 - We have seen that multiplying by a whole number is taking the multiplicand as many times as there are units in the multiplier.
Page 222 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced, add it to the principal, and deduct the payment from the sum total. If there be after payments made, compute the interest on the balance due to the next payment, and then deduct the payment as above; and, in like manner, from one payment to another, till all the payments are absorbed ; provided the time between one payment and another be one year or more.
Page 219 - The rule for casting interest, when partial payments have been made, is to apply the payment, in the first place, to the discharge of the interest then due. If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due.
Page 52 - III. — 1. Cut off the ciphers at the right of the divisor, and as many figures from the right of the dividend. 2. Divide the remaining figures in the dividend by the remaining figures in the divisor.
Page 282 - Hence, when the first term, the common difference, and the number of terms, are given, to find the last term...
Page 219 - If the payment be less than the interest, the surplus of interest must not be taken to augment the principal; but interest continues on the former principal until the period when the payments, taken together, exceed the interest due, and then the surplus is to be applied...