Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Volume 1W. Hilliard, 1808 - Mathematics |
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Page 14
... evident from the nature of notation . For any other disposition of the num bers would entirely alter their value ; and carrying one for eve- ry ten , from an inferior row or column to a superior , is evidently right , since an unit in ...
... evident from the nature of notation . For any other disposition of the num bers would entirely alter their value ; and carrying one for eve- ry ten , from an inferior row or column to a superior , is evidently right , since an unit in ...
Page 15
... being more convenient in practice . Now from the demonstration here given , the reason of the rule itself is evident ; for the excess of nines in each of two or METHOD OF PROOF . 1. Draw a line between the ARITHMETIC . 15 .
... being more convenient in practice . Now from the demonstration here given , the reason of the rule itself is evident ; for the excess of nines in each of two or METHOD OF PROOF . 1. Draw a line between the ARITHMETIC . 15 .
Page 18
... given numbers . Q. E. D. The truth of the method of proof is evident ; for the differ- ence of two numbers , added to the less , is manifestly equal to the greater . : 8. Sir Isaac Newton was born in the year 18 MATHEMATICS .
... given numbers . Q. E. D. The truth of the method of proof is evident ; for the differ- ence of two numbers , added to the less , is manifestly equal to the greater . : 8. Sir Isaac Newton was born in the year 18 MATHEMATICS .
Page 20
... evident , that we shall multiply all the parts of the multiplicand by all the parts of the multipli er ; or the whole of the multiplicand by the whole of the multi- 2. Begin at the right , and multiply the whole 20 MATHEMATICS .
... evident , that we shall multiply all the parts of the multiplicand by all the parts of the multipli er ; or the whole of the multiplicand by the whole of the multi- 2. Begin at the right , and multiply the whole 20 MATHEMATICS .
Page 21
... evident ; for 3x7 = 21 = 7x3 ; and , in general , 3 × 4 × 5 × 6 , & c . = 4 × 3 × 6 × 5 , & c . without any regard to the order of the terms ; and this is true of any number of factors whatever . The following examples are subjoined to ...
... evident ; for 3x7 = 21 = 7x3 ; and , in general , 3 × 4 × 5 × 6 , & c . = 4 × 3 × 6 × 5 , & c . without any regard to the order of the terms ; and this is true of any number of factors whatever . The following examples are subjoined to ...
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Common terms and phrases
affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
Popular passages
Page 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Page 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Page 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Page 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Page 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Page 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Page 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Page 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,